Syntax
#include <string.h> int strcoll(const char *string1, const char *string2);Description
strcoll compares the string pointed to by string1 against the string pointed to by string2, both interpreted according to the information in the LC_COLLATE category of the current locale.
strcoll differs from the strcmp function. strcoll performs a comparison between two character strings based on language collation rules as controlled by the LC_COLLATE category. In contrast, strcmp performs a character to character comparison.
strcoll returns an integer value indicating the relationship between the strings, as listed below: compact break=fit.
Value
Note:
This example compares the two strings passed to main.
#include <stdio.h>#include <string.h>
int main(int argc,char **argv)
{
int result;
if (argc != 3) {
printf("Usage: %s string1 string2\n", argv[0]);
}
else {
result = strcoll(argv[1], argv[2]);
if (0 == result)
printf("\"%s\" is identical to \"%s\"\n", argv[1], argv[2]);
else
if (result < 0)
printf("\"%s\" is less than \"%s\"\n", argv[1], argv[2]);
else
printf("\"%s\" is greater than \"%s\"\n", argv[1], argv[2]);
}
return 0;
/****************************************************************************
If the program is passed the following arguments:
"firststring" "secondstring"
The output should be:
"firststring" is less than "secondstring"
****************************************************************************/
}
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